Question

the edges of a triangular board are 6 cm, 8 cm and 10 cm . calculate the cost of painting it at the rate of 9 paise per cm²

Answer 1

IN ∆ABC
AB=6CM
BC = 8CM
AC= 10 CM
ACCORDING TO THE GIVEN MEASUREMENT IT SHOULD BE A RIGHT ANGLE∆
AB is a base 6cm BC is height 8cm and AC is hyptoneous 10cm (8^2+6^2=10^2) = (64 +36=100)
Area of ∆= 1/2 x base x height
=1/2 x 6 x 8
= 3x 8
= 24 cm ^2
Cost of
painting = 24 x9
= 231 paise
= ₹2.31