the edges of a triangular board are 6cm 8cm &10cm. find the cost of painting at the rate of 9 paise per cm square
Answers
Step-by-step explanation:
The sides of triangle are 6cm 8cm &10cm.
they are Pythagorean triplets, so they form a right angled triangle.
The area of such triangle = ½ base X height
= ½ X 6 X 8
= 24 cm²
Cost of painting = 24 X 9 paise
= 216 paise = Rs 2.16
Note- Herons formula can also be used to find the area of triangle but if it is for grade 10, that is not included in this year's syllabus
The cost of painting at the rate of 9 paise per cm square will be 216 paise
Step-by-step explanation:
GIVEN LENGTH
6 cm
8 cm
10 cm
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TO FIND
The cost of painting at the rate of 9 paise per cm square
___________________________
Area Of Triangle = ½ × Base × Height
___________________________
Let's find whether the Triangle is right ang triangle by Pythagoras Triplet
6² = 6 × 6 = 36
8² = 8 × 8 = 64
10² = 10 × 10 = 100
6² + 8² = 10²
36 + 64 = 100
100 = 100
The triangle is right angle triangle
___________________________
We know that,
Area Of Triangle = ½ × Base × Height
Area Of Triangle = ½ × 6 × 8
Area Of Triangle = ½ × 48
Area Of Triangle = 24
Area Of Triangle = 24 cm²
___________________________
We know that,
Cost Of Painting Of Per cm² = 9
24 cm² = 9 × 24
24 cm² = 216
24 cm² = 216 paise
The cost of painting at the rate of 9 paise per cm square will be 216 paise
