Question

the edges of a triangular board are 6cm 8cm and 10cm the cost of painting it at the rate70 paise per centimetre square​

Answer 1

Step-by-step explanation:

s=sum of edges/2 so s=12

s= half of perimeter

12×(12-6)×(12-8)×(12-10)=576

square root of 576 = 24

so the area of board is 24cm²

now multiply 24×70=1680

cost of painting is 1680 paise = 16.8 rs