Question

the edges of a triangular board are 6cm , 8cm and 10cm . The cost of painting it at rs. 0.09 per
​

Answer 1

Answer:

s=

2

a+b+c

=

2

6+8+10

=12

By Heron's formula,

Area of the triangle =

s(s−a)(s−b)(s−c)

=

12(12−6)(12−8)(12−10)

=

12(6)(4)(2)

=24cm

2

Cost of painting =9×24 paise =216 paise = Rs. 2.16.