The Edges of a Triangular Board are Given as 6cm, 8cm, and 10 cm. What will be the Cost of Painting it at the Rate of 20 Paisa/ cm ² is *
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Answer:
s= a+b+c/2
= 6+8+10/2
=12
By Heron's formula,
Area of the triangle =
√s(s−a)(s−b)(s−c)
=
√12(12−6)(12−8)(12−10)
=√12(6)(4)(2)
=24cm²
Cost of painting = 24×20= 480 paisa or rupees 4 and 80 paisa
hope it will help you
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