The edges of the triangular board 12cm ,16cm and 20 cm. Find the cost of printing the board at the rate of 15 paise per cm square.
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✦Question
The edges of the triangular board 12cm ,16cm and 20 cm. Find the cost of printing the board at the rate of 15 paise per cm square.
✦ANSWER.
![formula \: used formula \: used](https://tex.z-dn.net/?f=formula+%5C%3A+used)
![area \: of \: triangle = \frac{1}{2} \times b \times h area \: of \: triangle = \frac{1}{2} \times b \times h](https://tex.z-dn.net/?f=area+%5C%3A+of+%5C%3A+triangle+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+b+%5Ctimes+h)
☞NOW BACK ON QUESTION
GIVEN☞
Length =12cm
Base=16cm
hight=20cm
put in formula✍
![= \frac{1}{2} \times 16 \times 12 = \frac{1}{2} \times 16 \times 12](https://tex.z-dn.net/?f=+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+16+%5Ctimes+12)
![= 16 \times 6 = 16 \times 6](https://tex.z-dn.net/?f=+%3D+16+%5Ctimes+6)
![96 {cm}^{2} 96 {cm}^{2}](https://tex.z-dn.net/?f=96+%7Bcm%7D%5E%7B2%7D+)
Rate of printing =0.50paise per cm square
so , cost for 96cm^2 area = 0.50×96
![= 96\times .50 = 96\times .50](https://tex.z-dn.net/?f=+%3D+96%5Ctimes+.50)
![\frac{96 \times 50}{100} \frac{96 \times 50}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7B96+%5Ctimes+50%7D%7B100%7D+)
![48\: rs 48\: rs](https://tex.z-dn.net/?f=48%5C%3A+rs)
☞Hence cost of printing the board is 48 rs
The edges of the triangular board 12cm ,16cm and 20 cm. Find the cost of printing the board at the rate of 15 paise per cm square.
✦ANSWER.
☞NOW BACK ON QUESTION
GIVEN☞
Length =12cm
Base=16cm
hight=20cm
put in formula✍
Rate of printing =0.50paise per cm square
so , cost for 96cm^2 area = 0.50×96
☞Hence cost of printing the board is 48 rs
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4
Using herons formula :-
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