The edges of three cubes are 8 cm, 6 cm, and 1 cm, respectively. After melting these cubes a new cube is formed. Find the total surface of new cube.
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Answered by
24
Total surface area of all the 3 cube = total surface area of bigger cube
6(8^2+6^2+1^2)= TSA of bigger cube
6(64+36+1)
6×101
606cm^2 is your answer dear plz mark it as brainliast answer
6(8^2+6^2+1^2)= TSA of bigger cube
6(64+36+1)
6×101
606cm^2 is your answer dear plz mark it as brainliast answer
Answered by
61
HEYA!!!
HERE IS YOUR ANSWER,
=> Volume of first cube = 1 × 1 × 1 = 1 cm³.
=> Volume of second cube = 6 × 6 × 6 = 216 cm³.
=> Volume of third cube = 8 × 8 × 8 = 512 cm³.
=> Then Volume of bigger cube = 512 + 1 + 216 = 729 cm³.
=> So, side of bigger cube (a) = ³√729 = 9 cm.
=> Surface area of cube = 6 × a² = 6 × 9 × 9 = 486 cm².
HOPE IT HELPS YOU,
THANK YOU.☺️☺️
HERE IS YOUR ANSWER,
=> Volume of first cube = 1 × 1 × 1 = 1 cm³.
=> Volume of second cube = 6 × 6 × 6 = 216 cm³.
=> Volume of third cube = 8 × 8 × 8 = 512 cm³.
=> Then Volume of bigger cube = 512 + 1 + 216 = 729 cm³.
=> So, side of bigger cube (a) = ³√729 = 9 cm.
=> Surface area of cube = 6 × a² = 6 × 9 × 9 = 486 cm².
HOPE IT HELPS YOU,
THANK YOU.☺️☺️
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