Question

The effective capacitance between A and B is
C C
204%
B
21.
C C
H
이2
20
11​

Answer 1

Answer:

It is a Wheatstone bridge circuit and here C3C1=C4C2. Thus no charge will flow through C5=20μF.

As C1 and C3 are in series so C13=6+66×6=3μF

and also C2 and C4 are in series so C24=6+66×6=3μF

now C13 and C24 are in parallel so CXY=C13+C24=3+3=6μF