Physics, asked by karanharjani7, 10 months ago

The effective resistance between points A and B of the network shown in fig.
(Α) 2 Ω (Β) 3 Ω
(C) 6 Ω
(D) 12 Ω

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Answered by Anonymous
13

\huge\blue{Answer}

<body bgcolor ="r"> <font color =pink>In this case, the 3 resistors of 1Ω on the upper half of the circuit are connected in series and the combined resistance R1is given as 1+1+1=3Ω .

The 3 resistors of 2 ohms on the lower half of the circuit are connected in series and the combined resistance R2is given as 2+2+2=6Ω.

The resistances R1, R2 and 2Ω in the middle are connected in parallel. So the combined resistance R3 of this parallel connection is given as

1/3+ 1/2+ 1/6= 11 =1ohm. That is, the resistance in the closed loop is reduced to 1 ohm.

Now the total resistance R across the circuit is given as

R1 +R2 +R3=1+1+1=3Ω.

Hence, the value of the resistance in the circuit from A to B is 3Ω.

<marquee><font color= "red">Hope it helps you mark as brainliest please

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