Question

The effective resistance in between the points A to B in the circuit given below is ..
1) 23 ohm
2) 32 ohm
3) 12 ohm
4) 45 ohm

Answer 1

Redraw the circuit diagram as shown in the figure below.

Using the equivalent resistance formula

For series connection, $R_s = R_1 +R_2$

For parallel connection, $\dfrac{1}{R_p} = \dfrac{1}{R_1} +\dfrac{1}{R_2}$

Solving the  circuit using the above formulae we have

First 10 and 8 ohm resistances are in series. so their effective resistance is 18 ohm. This 18 ohm is in parallel with 9 ohm. so the effective resistance is 6 ohm. This 6 ohm is in series with 14 ohm, making the effective resistance as 20 ohm.

Now, 15 and 5 ohm are in series, so effective resistance is 20 ohm, which is in parallel with 20 ohm.So, the effective resistance becomes 10 ohm.This 10 ohm is in series with 6 ohm, making the effective resistance as 16 ohm. The 16 ohm is in parallel  to 48 ohm, which is 12 ohm.

This 12 ohm is in series with the 20 ohm, calculated above. So the effective resistance across the arm AB is 12+20 = 32 Ω

$R_{AB} = 32$ Ω

Answer 2

The answer is 32 ohms..

HOPE MY ANSWER IS CORRECT..

PLS MARK ME AS BRAINIEST.

HAVE A NICE DAY !!!