Question

the effective resistance of given two resistors when they are connected in series is 5 ohm and in parallel is 6/5 . find the values of resistance of given resistors

Answer 1

Answer:

2Ω and 3Ω

Explanation:

Let the resistors be R1 and R2

R1 + R2 = 5Ω => R1 = (5 - R2)Ω                        -----(1)

1/R1 + 1/R2 = 1/(6/5) = 5/6

R1+R2/R1.R2 = 5/6

Since R1 + R2 = 5

∴ 5/R1.R2 = 5/6

R1.R2 = 6

(5 - R2)R2 = 6

5R2 - R2² = 6

R2² - 5R2 + 6 = 0

(R2 - 3)(R2 - 2)

THERFORE, R2 = 3Ω or R2 = 2Ω

THERFORE, R1 = 2Ω or R2 = 3Ω