Question

The effective resistance of three resistors connected in parallel is 60/47 Ω. When onewire breaks, the effective resistance becomes 15/8 ohms. Find the resistance of thewire that is broken.

Answer 1

Answer:

The effective resistance of three resistors connected in parallel is 60/47 Ω. When one wire breaks, the effective resistance becomes 15/8 ohms

Answer 2

Answer:

4Ω

Explanation:

Effective resistance of three resistors = 60/47Ω (Given)

Let the three resistors be = Ra , Rb , Rc

Let the total resistance of the three resistors be = R3

Let the total resistance of the two resistors be = R2

Therefore, total resistance of three resistors -

1/R3 = 1/Ra + 1/Rb + 1/Rc = 47/60

When one wire breaks down, let the wire be of resistance be = Ra

1/R2 = 1/Rb + 1/Rc = 8/15

Thus,

1/Ra + 8/15 = 47/60

Ra = 4

Thus, the resistance of the wire that is broken is 4Ω.