Physics, asked by smdyaseen5266, 1 year ago

The effective resistance of two resistor in parallel is 12/7 coulomb. if one of the resistor is disconnected the resistance become 4 coulomb. the resistance of other resistor is

Answers

Answered by brunila
5
Two resistors R1,R2 are connected in parallel so resultant resistance is
1/R =1/R1 + 1/R2
given resultant resistance = R = 12/7 ohm
if one resistor is disconnected i.e R2=0 then R=R1 = 4 ohm
Now,
   1/R2 = 1/R - 1/R1
            = 7/12 - 1/4
            = (7-3)/12 
            =  4/12 
            = 1/3 ohm
therefore the resistance of other resistor is 3 ohm
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