The effective resistance of two resistor in parallel is 12/7 coulomb. if one of the resistor is disconnected the resistance become 4 coulomb. the resistance of other resistor is
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Two resistors R1,R2 are connected in parallel so resultant resistance is
1/R =1/R1 + 1/R2
given resultant resistance = R = 12/7 ohm
if one resistor is disconnected i.e R2=0 then R=R1 = 4 ohm
Now,
1/R2 = 1/R - 1/R1
= 7/12 - 1/4
= (7-3)/12
= 4/12
= 1/3 ohm
therefore the resistance of other resistor is 3 ohm
1/R =1/R1 + 1/R2
given resultant resistance = R = 12/7 ohm
if one resistor is disconnected i.e R2=0 then R=R1 = 4 ohm
Now,
1/R2 = 1/R - 1/R1
= 7/12 - 1/4
= (7-3)/12
= 4/12
= 1/3 ohm
therefore the resistance of other resistor is 3 ohm
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