The efficiencies of A, B & C are in the ratio of 2:3:5. Working together, they can complete a task in 6 days. In how many day will A alone complete 20% of that task ?
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Answer:
A alone complete 20% of the task in 6 Days
Step-by-step explanation:
Let say A's 1 Day work = 2D
then B's 1 day Work = 3D
& C's 1 day Work = 5D
A+ B + C together 1 days work = 2D + 3D + 5D = 10 D
Working together, they can complete a task in 6 days
=> Total Work = 6 * 10D = 60D
20% of that task = (20/100) * 60D = 12D
Time Taken by A to complete 12 D work = 12D/2D = 6
A alone complete 20% of the task in 6 Days
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