Question

the efficiency of a,b,and c are in the ratio 4:5:6. they can together complete a work in 20 days . in how many days A alone will complete that work?​

Answer 1

Answer:

75

Step-by-step explanation:

total work = (4+5+6) × 20 = 300 units

A alone = 300/4 = 75 days

Answer 2

A alone will complete that work in 75 days

Solution:

According to question,

The efficiency of a, b and c are in the ratio 4:5:6 and they can together complete a work in 20 days  

Total work = Total Efficiency $\times$ no. of days

Total work = (4+5+6) $\times$ 20 = 15 $\times$ 20  

Total work = 300

So, A alone can complete the work in

Total Work = Efficiency of A $\times$ no. of days

$\begin{array}{l}{300=4 \times \text { no. of days }} \\\\ {\text { no. of days }=\frac{300}{4}} \\\\ {\text { no. of days }=75}\end{array}$

So, A alone can complete the work in 75 days

Learn more about Efficiency and work

Efficiency of A,B and C is in the ratio 4:5:6. What is the ratio of the time in which they complete the work?

https://brainly.in/question/5322371

The ratio of the capacity to do work of a and b is 3 : 2. if they together can complete a work in 18 days, then how long does a take to complete the work alone?

https://brainly.in/question/3244164