Question

the efficiency of a carnot engine is 50% when the same temperature is 27 degree Celsius it is desired to increase the efficiency to 60% find the increase in source temperature​

Answer 1

Efficiency n = (t2-t1)/ t2 

Where t2 is the source temperature and t1 is the sink temperature  

Now when the efficiency is 50% 

0.5 = (t2-500)/T2 

T2 = 1000K 

When the efficiency is  

0.6 = (t2-t1)/T2 

The required temperature of the sink will be  

T1 = 400k

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