Physics, asked by kamalmind486, 1 year ago

The efficiency of a Carnot engine is 60%.if the temperature of source is 127°celsius ,the sink must be maintained at

Answers

Answered by satbhavya6

0

Efficiency (n) =60%

Temp at source=127+273=400K

60/100=1-T/400

60/100=400-T/400

240=400-T

T=400-240

=160K

Temperature at sink is 160K

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