Question

The efficiency of a Carnot engine operating between temperatures 100 °C and -23°C will be.
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Answer 1

Q]____?

( 100 + 23 ) / 373 !

Explanation:

Efficiency of Carnot engine is given by

n = 1 = T2 / T1 = T1 - T2 / T1 _[i]

Given,

T1 = temperature of reservoir

T1 = 100 + 237 = 373 K

T2 = temperature of sink

T2 = -23 + 273 = 250 K

Substituting in Eq [i] we get,

∴ n = 373 - 250 / 373 = 123 / 373

∴ n = 100 + 23 / 373

Answer 2

Answer:

$\boxed \purple {answer is 100 + 23 \div 373}$

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