Question

The efficiency of a Carnot's heat engine is 0.3. If on reducing the temperature by 50° C, the efficency increases to 0.4. Calculate the temp of source and sink.
​

Answer 1

Answer:

η=Total amount of heat absorbed per cycleNet work done per cycle

or η=Q1W

∴η=Q1Q1−Q2

or η=1−Q1Q2

as Q1Q2=T1T2

∴η=1−T1T2....(i)

where, T2 is temperature of sink and T1 is the temperature of the sources.

Here, η=50%

T2=50∘C=273+50

=323 K

Putting these values in Eq. (i), we get

10050=1−T13

Explanation:

thank you! don't forget to like...