Question

The efficiency of a carnots engine working between two temperature is 0.2.When the temperature of the source is increased by 25degree celsius the efficiency increases yo 0.25. Find the temperature of the source and the sink

Answer 1

Answer:

Here T1=327°C=327+273=600°K assuming the sink temperature=T2°K and efficiency of that engine is 25%=0.25

Now the formulae for efficiency=1-(T2/T1)

=1-T2/600=0.25=>T2/600=1–0.25=0.75

=>T2=600×0.75=450°K=>450–273=177°C.Ans..