Question

The efficiency of a thermodynamic cycle 1-2-3-1 is 20% and for another thermodynamic cycle 1-3-4-1 is 10%.

Determine the efficiency of the combined cycle.

Diagram given below.

Forth option is 26

Answer 1

Answer:

28%

Explanation:

20%=1/5=1-(Qa/Qb)

Qa=4/5 Qb

10%=1/10=1-(Qa'/Qa)

Qa'=9/10 Qa=36/50 Qb

Efficiency = 1-(Qa'/Qb)= 1-36/50= 14/50 = 28%