Physics, asked by Juned7205, 9 months ago

The efficiency of carnot engine at a particular source nd sink temp is 2/3 if the sink temp is reduced by 100 °c the engine efficiency become 3/4 the temp of the source will be

Answers

Answered by harsharora111
0

Answer:

1200Kelvin

n = 1- T2/T1

T2 - Temperature of sink

T1 - Temperature of source

Put Value

Thanks for Reading

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