Physics, asked by avneet8329, 3 months ago

The efficiency of carnot engine when source temperature
is T₁ and sink temperature is T2 will be
(a) T₁ - T₂/T₁
(b) T₂ - T₁/T₂ (c) T₁ - T₂/T₂
(d)T₁/T₂

❣️

Answers

Answered by tusharrastogi27

13

Answer:

Option (A)

T₁ - T₂/T₁

Mark me as brainliest please.....!!!

Answered by Anonymous

10

Answer:

( a ) T₁ - T₂/T₁

Explanation:

The efficiency of carnot engine when source temperature is T₁ and sink temperature is T2 will be

T₁ - T₂/T₁ .

where,

T₁ = source temperature

T₂ = sink temperature

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