Physics, asked by Anonymous, 19 days ago

The efficiency of carnot engine when source temperature
is T₁ and sink temperature is T2 will be
(a) T₁ - T₂/T₁
(b) T₂ - T₁/T₂ (c) T₁ - T₂/T₂ ​

Answers

Answered by raviktthakur663
0

Answer:

Correct answer is a.

Explanation:

efficiency = output / input.

Output = q1 - q2

input = q1

q1/q2 = T1/T2

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