Question

The efficiency of carnot engine when source temperature
is T₁ and sink temperature is T2 will be
(a) T₁ - T₂/T₁
(b) T₂ - T₁/T₂ (c) T₁ - T₂/T₂
(d)T₁/T₂​​​

Answer 1

Answer:

• The required option is (a) T1-T2/T1

Step-by-step explanation:

Topic

• Thermodynamics

According to the Question

It is given that,

• Source Temperature = $T_1$
• Sink Temperature = $T_2$

We have to calculate the effeciency of carnot engine .

As we know that efficiency of carnot engine is calculated by

$\boxed{\bf{\eta= 1 -\frac{T_2}{T_1}}}$

by putting the value we get

$\sf\implies\eta = 1-\frac{T_2}{T_1} \\\\\\\sf\implies\eta = \frac{T_1 - T_2}{T_1} \\\\\boxed{\bf{Hence, the~required~ option ~ is ~ (a) \frac{T_1-T_2}{T_1} }}$

Answer 2

Answer:

The efficiency of carnot engine when source temperature

is T₁ and sink temperature is T2 will be

(a) T₁ - T₂/T₁

(b) T₂ - T₁/T₂ (c) T₁ - T₂/T₂

(d)T₁/T₂

Step-by-step explanation:

(a) T₁ - T₂/T₁ ✅