Physics, asked by khansaba2721, 1 month ago

The efficiency of heat engine working between 27°C
and 327°C may be Tr = 27°C +27
To 73.27​

Answers

Answered by 4ag
0

The efficiency of the cycle is given as η=1−T1T2. Here T1 is the temperature of the source and T2 is the temperature of the sink. . Thus we get η=1−600300=50%. The efficiency is to be increased by 10%. Thus the new efficiency is 55%. Thus we get 0.55=1−T1300

or

T1=0.45300=667K

Thus the increase in temperature of the source is 667−600=67oC

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