The efficiency of the Carnot engine working between temperatures 177°C and 77°C will be:
A. 22.22%
B. 23.23%
C. 25.25%
D. 30.30%
Right answer is A.
Explanation:
T1=177°C + 273=450 K
T2=77°C + 273=350 K
E=(1-T2/T1) ×100
E=(1-350/450)×100
E={(450-350)/450} ×100
E=(100/450)×100
E=0.2222×100
E=22.22%
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Answers
Answered by
2
Answer:
T1 = 177℃ = 177+273 =450K
T2 = 77℃ = 77+273 =350K
Thermal efficiency = ( T1 - T2 /T1 ) ×100
= (450-350/ 450) ×100
=(100 /450)×100 =10000 /450 = 22.22%
Answered by
1
Answer:
A. 22.22%
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