Question

the efficiency of the heat engine working between 327°c and 27°c the temperature of the source increased by​

Answer 1

Answer:

Hey mate your ans here

To calculate efficiency the formula that is use

Efficiency = 1-T1/T2

According to the question

T1 = 327°c = 327+273 = 600k

T2 = 27°c = 27 + 283 = 300k

Now, efficiency equal to,

E =1- 300/600

E= (600-300)/600

E = 1/2 J

E = 0.5 joules

Hope it will help you ✌