The effort arm of a lever is 120 cm long and the load arm is 80 cm long. What is the effort needed to raise a load of 60 N weight? What is the mechanical advantage of this lever?
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Effort Arm /Load .Arm =Load/Effort
120/80 = 60/Effort
Effort = 40 N
Mechanical .Advantage = Load/Effort = 6O/40=3/2=1.5
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Answer:
the answer is
Explanation:
Effort Arm /Load .Arm =Load/Effort
120/80 = 60/Effort
Effort = 60 N
Mechanical .Advantage = Load/Effort = 6O/60=6/6= 1 \
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