Physics, asked by jenessaraj5d162382, 21 hours ago

The effort arm of a lever is 120 cm long and the load arm is 80 cm long. What is the effort needed to raise a load of 60 N weight? What is the mechanical advantage of this lever?​

Answers

Answered by Ronithreddy
3

Effort Arm /Load .Arm =Load/Effort  

120/80 = 60/Effort

Effort = 40 N

Mechanical .Advantage = Load/Effort = 6O/40=3/2=1.5

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Answered by tejasvsharma370
2

Answer:

the answer is

Explanation:

Effort Arm /Load .Arm =Load/Effort  

120/80 = 60/Effort

Effort = 60 N

Mechanical .Advantage = Load/Effort = 6O/60=6/6= 1 \

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