Question

The effort arm of a lever is 2 m long and the load arm is 4 m long. Find the effort required to load of 10 N.​

Answer 1

Answer:

Effort required to lift the load to 21 N is

14 N.

Explanation:

Given :

• Load arm of the lever, L' = 2 m

. Effort arm of the lever, E' = 3 m Load to be lifted, L = 21 N

To find :

Effort required to lift the load, E = ?

Knowledge required :We know that in case of a lever,

L XL = EXE'Where,

L = Load to be lifted

• E = Effort required to lift the load • L' = Load arm or the lever

. E' = Effort arm of the lever

From the above equation, we get :

=> L = (Ex E')/L' => L/E = E'/L'

.. Load/Effort = Effort arm/Load arm

Solution :

By using the relation between load & Effort and Load arm & and Effort arm, we get :

=> L/E = E'/L'

=> 21/E = 3/2

-> 21/5x 2-2

By using the relation between load & Effort and Load arm & and Effort arm, we get :

=> L/E = E'/L'

=> 21/E = 3/2

=> 21/E x 2 = 3

=> 42/E = 3

=> 1/E = 3/42

=> 1/E = 1/14

=> 14 = E

.: Effort = 14 N

Therefore,

Effort required to lift the load, E = 14 N