Question

the effort arm of a lever is 50 m and the load arm is 5 m.calculate the effort force required to lift a load of 200 N.​

Answer 1

Answer:

Effort arm = 50 m

Load arm = 5 m

Load = 200 N

Effort force = ?

We know that,

Load x Load arm = Effort x Effort arm

200 N x 5 m = Effort x 50 m

Effort = 200 x 5/50

Effort = 20

NExplanation:

Answer 2

Answer: The effort force required to lift a load of 200 N is 2000 N.

The effort force required to lift a load of 200 N can be calculated using the principle of leverage. The principle states that the effort force required is inversely proportional to the length of the effort arm and directly proportional to the length of the load arm.

Let's call the effort force F_effort. Using the principle of leverage, we can write the following equation:

                   F_effort/F_load = Effort arm/Load arm

                   F_effort/200 N = 50 m/5 m

                     F_effort/200 N = 10

                   F_effort = 200 N * 10

                     F_effort = 2000 N

So, the effort force required to lift a load of 200 N is 2000 N.

Learn more about the principle of leverage here

https://brainly.com/question/28897811

Learn more about the  effort force here

https://brainly.in/question/48113802

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