the effort arm of a lever is 5m long and its load arm is 2m long. Find the effort needed to raise a load of 70 kgwt.
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The load arm and effort arm of a lever are 10 cm and 50 cm, respetively. The load and effort are applied on the opposite sides of the fulcrum. ... Since the fulcrum lies in between the load and effort, it is class I lever.
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Answer:
load/effort=effort arm/load
70/effort=2/5
effort =(5*70)/2
=350/2=175N
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