The eight term of an Ap is half of its second term and the elevent term exeeds one third of its fourth term by 1 . Find the 15th term
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8th term = a+7d
2nd term= a+d
ATP
a + 7d = (a+d)/2
2a + 14d = a+d
a = -13d ..........…………¹
11th term = a + 10d
4th term = a+3d
ATP
a+10d =(a+3d)/3 + 1
a+10d= (a +3d + 3)/3
3a+30d= a+3d+3
2a+27d= 3 (from ¹)
-26d +27d = 3
d=3
15th term = a+14 d
= -13d + 14d
=d
= 3
therefore the 15th term of the ap is 3
2nd term= a+d
ATP
a + 7d = (a+d)/2
2a + 14d = a+d
a = -13d ..........…………¹
11th term = a + 10d
4th term = a+3d
ATP
a+10d =(a+3d)/3 + 1
a+10d= (a +3d + 3)/3
3a+30d= a+3d+3
2a+27d= 3 (from ¹)
-26d +27d = 3
d=3
15th term = a+14 d
= -13d + 14d
=d
= 3
therefore the 15th term of the ap is 3
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