The eight term of an arithmetic sequence is 40 calculate the sum of first 15 term
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1
Answer:
600
Step-by-step explanation:
a8= 40
a+(8-1)d = 40
a+7d = 40 1
NOW
n= 15
s15= 15/2[2a+(15-1)d]
s15 = 15/2[2a + 14d]
s15 = 15/2 × 2 [2a + 7d]
s15 = 15× 40. from 1
s15 = 600
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