The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by appliying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.
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Hey folk...
here is ur answer:
energy. of photoelectron = hc / λ
h = 6.62 * 10^-34 Js
c = 3 * 10^8 m/s
λ = 256.7 * 10^-9
substituting above values , energy will come out to be 7.744 * 10^-19 J
K.E. = eV = 0.35 * 1.602 * 10^-19
= 0.56 * 10^-19 J
Threshold energy = work function
=> (7.747 - 0.56) * 10^-19
=> 7.184 * 10^-19
work fuction = ( 7.184 * 10^-19 ) / (1.602 * 10^-19)
= 4.48 eV
HOPE IT HELPS...
#Mme
here is ur answer:
energy. of photoelectron = hc / λ
h = 6.62 * 10^-34 Js
c = 3 * 10^8 m/s
λ = 256.7 * 10^-9
substituting above values , energy will come out to be 7.744 * 10^-19 J
K.E. = eV = 0.35 * 1.602 * 10^-19
= 0.56 * 10^-19 J
Threshold energy = work function
=> (7.747 - 0.56) * 10^-19
=> 7.184 * 10^-19
work fuction = ( 7.184 * 10^-19 ) / (1.602 * 10^-19)
= 4.48 eV
HOPE IT HELPS...
#Mme
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