Question

The elastic potential energy of a stretched spring is given byE=50x*x.where x is the displacement in meter and E is in joule, then the force constant of the spring is​

Answer 1

Explanation:

comparing given eqn with

1/2* k * x^2

where k is spring constant

we get

1/2* k = 50

k = 100 N/m

Answer 2

Explanation:

comparing given eqn with

1/2* k * x^2

where k is spring constant

we get

1/2* k = 50

k = 100 N/m