Question

the elastic potential energy of stretched spring is given by E equals to 50 x square where where X is the displacement in metre and E is in joule then the force constant of the spring is​

Answer 1

Explanation:

potential energy of spring =

1/2 * k * x^2

where k is spring constant

comparing given eqn with the above eqn we get

1/2 * k = 50

k = 100 N/m

Answer 2

Explanation:

comparing given eqn with

1/2* k * x^2

where k is spring constant

we get

1/2* k = 50

k = 100 N/m