the elastic potential energy of stretched spring is given by E equals to 50 x square where where X is the displacement in metre and E is in joule then the force constant of the spring is
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Explanation:
potential energy of spring =
1/2 * k * x^2
where k is spring constant
comparing given eqn with the above eqn we get
1/2 * k = 50
k = 100 N/m
Answered by
0
Explanation:
comparing given eqn with
1/2* k * x^2
where k is spring constant
we get
1/2* k = 50
k = 100 N/m
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