Question

The elastic potential energy stored in a spring having a compression 10cm is...

Answer 1

Answer ⇒ Elastic potential energy of the spring is 5 × 10⁻³k J.

Explanation ⇒ Using the formula,

Elastic Potential energy of the spring = 1/2 × kx²

where, k is the spring constant and x is the elongation in the spring.

It is given that x = 10 cm or 0.1 m.

Value of k is not given in the question, thus we will find he answerr in terms of k only.

Therefore,

U = 1/2 × k × (0.1)²

∴ U = k/200

∴ U = 5 × 10⁻³k J.

Hence, the Elastic potential energy of the spring is 5 × 10⁻³k J.

Hope it helps.

Answer 2

Answer:

The elastic potential energy of the spring is 0.05 J.

Explanation:

The elastic potential energy stored in a spring having a compression because when the compression of the spring is done the potential energy increases.

The elastic potential energy is given by the formula:

$\Delta P E=\frac{1}{2} k x^{2}$

Where,

k = Spring constant

x = Displacement = 10 cm (given)

On substituting the values,

$\Rightarrow \Delta P E=\frac{1}{2} k\left(10 \times 10^{-2}\right)^{2}$

$\Rightarrow \Delta P E=\frac{10^{-2}}{2} k=\frac{0.01}{2} k$

$\therefore \Delta P E=0.005(k) \ J$

When the string is stretched or compressed against the restoring force of the spring is done, this type of work done is stored as elastic potential energy in the spring.