Question

The electric current in a charging R-C circuit is given by i = i e^(-t/RC) where i , R and C are constant parameters of the circuit and t is time . Let i = 2.00 A , R =6.00x10^5 ohm and C = 0.500 μF.

(A) Find the current at t=0.3 s
(B) Find the rate of change of current at t=0.3 s
(C) Find approximately the current at t=0.31 s

Answer 1

Thanks for asking the question!

ANSWER::

Given:-
i = i₀e^(-t/RC)

i = 2A 
R = 6 x 10⁻⁵ ohm 
C = 0.0500 x 10⁻⁶ F = 5 x 10⁻⁷ F

(a) i = 2 x e^(-0.3/(6 x 5 x 10⁻⁷)) = 2 x e^(-0.3/0.3) = 2/e Ampere

(b) di/dt = -i₀e^(-t/RC) / RC 
     t = 0.3 s
     di/dt = -2 e^(-0.3/0.3)/0.30 = -20/3e Ampere / second 

(c) t = 0.31 s 
     i = 2e^(-0.3/0.3) = 5.8/3e Ampere

Hope it helps!

Answer 2

Explanation:

same as brainlest it's