Question

The electric dipole moment of the system as shown in fig is


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Answer 1

Answer:

As Electric Dipole is A vector quantity

P = qnet × a

Explanation:

P1 = ( -2q + q ) × a

P2 = same

Pnet = root 2 q a

Option C

Answer 2

Explanation:

split the -2q charge into -q and -q

dipole moment will be in the direction of -q to +q

dipole moment=magnitude of one of the charge×distance

p=q×a

p1=q×a

p2=q×a

pnet=under root[ (qa)^2+(qa)^2+(qa)(qa)cos(pie/2)]

p net= under root[2(qa)^2]

pnet =

we got option c