Question

The electric field associated with a monochromatic beam is 1.2 × 1015 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

Answer 1

Answer:

2.9ev answer

energy can be calculated by the formula equals to hv then convert it into electron volt unit then put it in the Einstein formula of modern physics then the answer will be calculated as 2.9 electron volt

Answer 2

A photon's average kinetic energy is 0.486 eV.

Explanation :

Step 1:

Given data in the question  

Monochromatic Pulse electric field, $E=1.2 \times 10^{15} times/second$

Frequency, $v=\frac{1.2 \times 10^{15}}{2}=0.6 \times 10^{15} \mathrm{Hz}$

the metal surface of the Work function, ϕ = 2.0  eV

Step 2:

Kinetic energy from Einstein's photoelectric equation,

$x^{2} \begin{aligned}&K=h v-\phi_{0}\\&K=\frac{6.63 \times 10^{-34} \times 0.6 \times 10^{15}}{1.6 \times 10^{-19}}-2\\&K=\frac{3.978 \times 10^{-19}}{1.6 \times 10^{-19}}-2\\&K=\frac{3.978}{1.6}-2\\&K=2.486-2\end{aligned}$  

         = 0.486 eV