The electric field at 2R from the centre of a uniformly charged non conducting sphere of radius R is E. The electric field at a distance R/2 from the centre will be 1) zero2) 2E3) 4E4) 16E
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328
Answer is Option 2) 2 E.
Let the total charge on the sphere be = Q.
It is nonconducting dielectric sphere. It is uniformly charged.
So charge density per volume = ρ = Q/[4/3 π R³] = 3Q/(4πR³) ---(1)
Electric field at distance 2 R due to the sphere
= E = 1/[4πε] * Q/(2R)² --- (2)
For finding the electric field at a distance R/2 from the center of sphere, we need to take into account the charge enclosed within the sphere of radius R/2 only. This is obtained from Gauss's law for flux coming out of a closed spherical surface of radius R/2.
Q1 = charge enclosed = ρ * volume
= ρ * 4/3 π (R/2)³
= π/6 ρ R³ = π/6 * 3Q/(4πR³) * R³
= Q/8
E1 = 1/[4πε] * Q1/(R/2)²
= 1/[4π] * (Q/8) * 4/R²
= 1/[4π] * Q/(2R²)
= 2 E
Let the total charge on the sphere be = Q.
It is nonconducting dielectric sphere. It is uniformly charged.
So charge density per volume = ρ = Q/[4/3 π R³] = 3Q/(4πR³) ---(1)
Electric field at distance 2 R due to the sphere
= E = 1/[4πε] * Q/(2R)² --- (2)
For finding the electric field at a distance R/2 from the center of sphere, we need to take into account the charge enclosed within the sphere of radius R/2 only. This is obtained from Gauss's law for flux coming out of a closed spherical surface of radius R/2.
Q1 = charge enclosed = ρ * volume
= ρ * 4/3 π (R/2)³
= π/6 ρ R³ = π/6 * 3Q/(4πR³) * R³
= Q/8
E1 = 1/[4πε] * Q1/(R/2)²
= 1/[4π] * (Q/8) * 4/R²
= 1/[4π] * Q/(2R²)
= 2 E
kvnmurty:
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2
Answer:
Explanation: surface charge density sigma=q/4/3Pi r^3 q=sigma×4/3pi r^3
E=Kq/r^2
Where r is distance surface charge and test charge according to question, sigma=q'/4/3pi r^3 q'=sigma×4/3pi (r/2)^3 = 8×sigma×4/3pi r^3/8=q/8 with the help of Gouce E'=Kq'/(r/2)^2 =Kq/8/(r^2/4) = 2E
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