The electric field at a point near an infinite thin sheet of charged
conductor is :
(a) Eo o (b)
1.
olu
(c) 2 60
(a) zce,
Answers
Hyy Dude
▓█►─═ Ans : E = σ/2ε₀
first understand what is difference between sheet and plate in electrostatic ?
sheet => both side charge
plate => one side charge
here , mentioned sheet , then surely charge will appear in both side of conductor .
now, Use the Gauss concept for finding electric field .
Let Q present in charged sheet conductor .
because , I clearify that both side charge presents in sheet .
so, each side charge share = Q/2
so, each side charge share = Q/2 now, Gauss formula,
Φ = Qnet/2ε₀
here , Qnet at one side = Q/2
also we know, Φ { electric flux near the surface of sheet } = E{electric field near the surface} × A { cross section Area of gaussian surface is chosen by us }
so, EA = Q/2ε₀
E = Q/2Aε₀= {Q/A}/2ε
we know, Q/A = surface charge density = σ
we know, Q/A = surface charge density = σE = σ/2ε₀
hence, electric field at a point near an infinite sheet of charged conductor is σ/2ε₀ ═─◄█▓
Hope it's helps you ✨