The electric field Ē at each point on a rectangular surface has a magnitude of 350 N/C and makes an angle of 50° with the normal to the surface n. The dimensions of the surface are 20 cm by 15 cm. Calculate the electric flux for the surface.
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For a uniform electric field passing through a plane surface,
ϕE=E→⋅A→=EAcosθ, where θ is the angle between the electric field and the normal to the surface,
(a) The electric field is perpendicular to the surface so θ=0o
ϕE=(3,50×103N/C)[(0.350m)(0.700m)]cos0o
=858N⋅m2/C
(b) The electric field is parallel to the surface θ=90o, so cosθ=0 and the flux is zero.
(c) For the specified plane,
ϕE=(3,50×103N/C)[(0.350m)(0.700m)]cos40.0o
=657N⋅m2/C
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