Physics, asked by Rajeshprakashrao, 11 months ago

the electric field at point P due to a charged ball is given by Ep=
kq \div  {r}^{2}

to measure E at a point P a test charge qo is placed at point P and measure electric force F upon test charge check whether F/qo is equal to
kq \div  {r}^{2}
or not

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Answered by Anonymous
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Divergence of a field and its interpretation

electrostatics maxwell-equations gauss-law dirac-delta-distributions

The divergence of an electric field due to a point charge (according to Coulomb's law) is zero. In literature the divergence of a field indicates presence/absence of a sink/source for the field.

However, clearly a charge is there. So there was no escape route.

To resolve this, Dirac applied the concept of a deltafunction and defined it in an unrealistic way (the function value is zero everywhere except at the origin where the value is infinity). However the concept was accepted and we became able to show that

∇⋅ →E =0, everywhere except at the origin.

Answered by saivivek16
0

Answer:

Explanation:

Divergence of a field and its interpretation

electrostatics maxwell-equations gauss-law dirac-delta-distributions.

Hope it will help you

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