Question

The electric field component due to charge inside the cube of side 0.1m are shown calculate the flux through cube and charge inside the cube​

Answer 1

Answer:

Given length of the cube=0.1 m

E

y

=0, E

z

=0, E

x

=500

C−m

N

the flux through the cubeψ=∫E.ds=∫(E

x

i+E

y

j+E

z

k).ds=∫E

X

i.ds=E

x

x=αx=500x

ψ=(E

x

.A)

t=0.1

+(E

x

.A)

x=0.2

=E

x

Acos180+E

x

cos0=500×0.01×(−1)+500×0.2×0.01=−0.5+1=0.5

Cm

2

N

charge inside the cubeψ=∫E.ds=

E

0

q

⟹q=0.5×E

0

=0.5×8.85×10

−12

=4.425×10

−12

C

Explanation:

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