Question

The electric field components in a region of space is given as Ex=200, Ey=Ez=0.
(All quantities are in SI units)
Find charge enclosed within the cube shown in the figure. (a=0.2m)​

Pls answer Asap! Thank u in adv

Answer 1

Answer:

charge enclosed is zero because flux is also zero

Answer 2

The charge enclosed within the cube is zero.

Given:

$E_{x}$=200, $E_{y}$ = $E_{z}$= $0$

To Find:

Charge enclosed within the cube.

Solution:

We have been given that $E_{y}$ = $E_{z}$= $0$, i.e. electric field along y and  axes is zero.

According to Gauss law,

∮ E.ds =  $Q_{enclosed}$ / ∈$o$

Since E = 0 along the x and y axes, $Q_{enclosed}$= 0.

Now, along the x-axis, $E_{x}$=200 i.e. electric field is constant and does not vary with distance from the origin.

Therefore net incoming flux = net outgoing flux

Hence Ф$_{net}$ = 0.

We know that electric flux for a  surface is given by

Ф=   $Q_{enclosed}$/ ∈$o$

Since Ф= 0,

$Q_{enclosed}$ = 0.

Therefore, charge enclosed within the cube is zero.

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