Question

The electric field due to a charge of 5x10⁻⁶ C at a distance of 5 cm from it is ---------​

Answer 1

Answer:

Given: q=5×10 −6C

F=2×10 −3N

We know that, Electric field intensity=E= qF = 5×10 −6

2×10 −3

=400N/C

Answer 2

Answer:

1.8×10^8

Explanation:

formula applied :- E=(kQ) /r^2