Physics, asked by omghogale885, 10 months ago

The electric field due to a point charge at a distance 1 m from it is 90 N/C. The magnitude of the charge is

Answers

Answered by amitnrw
1

Charge  = 10⁻⁸ C  if The electric field due to a point charge at a distance 1 m from it is 90 N/C

Explanation:

E = k q/d²

E = 90  N/C

d = 1 m

k = 9 * 10⁹ Nm²C⁻²

q =  ?

90  = 9 * 10⁹    * q/1²

=>  q = 10 /10⁹  C

=> q = 10⁻⁸ C

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