Question

the electric field due to a point charge at a distance 1m is 900N/C. The magnitude of charge is? ​

Answer 1

Explanation:

answer is in the above picture

Answer 2

Answer:

The magnitude of electric charge will be $100.11 X 10^{-9}$ coulombs

Explanation:

Coulomb's law states that the magnitude of the electric field ($E$) produced by a point charge with a charge of magnitude $Q$, at a point a distance $r$ away from the point charge, is given by the equation

$E=\frac{kQ}{r^{2} }$, where $k$ is a constant with a value of $8.99 X 10^{9}$ $\frac{Nm^{2} }{C^{2} }$

As per the given equation and the information,

$Q=\frac{Er^{2} }{k}$ = $\frac{900 X 1^{2}}{ 8.99 X 10^{9}}$

∴$Q= 100.11 X10^{-9}$$C$